How do you find the zeros of $y = x^2 + 5x + 3$ using the quadratic formula?

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Answer 1 · 2015-11-23T03:20:29

$(-5+-sqrt(13))/2$

For the general quadratic equation $ax^2+bx+c$ , the quadratic formula states that $x=(-b+-sqrt(b^2-4ac))/(2a$ .

In your quadratic, $a=1$ , $b=5$ , and $c=3$ .

We can plug in values.

$x=(-5+-sqrt(5^2-4(1)(3)))/(2(1))=(-5+-sqrt(13))/2$

How do you find the zeros of y = x^2 + 5x + 3 y = x^2 + 5x + 3 using the quadratic formula?