How do you find the zeros of y = -9x^2 + 18x -2 using the quadratic formula?

1 Answer
Nghi N.
Jul 10, 2016

(3 +- sqrt7)/3

Explanation:

Use the improved quadratic formula (Google Search)
y = -9x^2 + 18x - 2 = 0
D = d^2 = b^2 - 4ac = 324 - 72 = 252 = 36(7) --> d = +- 6sqrt7
There are 2 real roots:
x = -b/(2a) +- d/(2a) = -18/-18 +- (6sqrt7)/18 = 1 +- sqrt7/3
x = (3 +- sqrt7)/3

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