How do you find the zeros of $y = - 3 x^{2} - 5 x + 23$ $y = -3x^2 - 5x + 23$ using the quadratic formula?

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How do you find the zeros of $y = - 3 x^{2} - 5 x + 23$ $y = -3x^2 - 5x + 23$ using the quadratic formula?

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Answer 1 · 2015-11-26T02:51:28

$x = \frac{- 5 \pm \sqrt{301}}{6}$ $x= (-5+-sqrt301)/6$

Explanation:

To find the zeros, put y=0 and apply the quadratic formula.

Accordingly, $- 3 x^{2} - 5 x + 23 = 0$ $-3x^2 -5x +23=0$ ,

Or, $3 x^{2} + 5 x - 23 = 0$ $3x^2 +5x -23=0$

$x = \frac{- 5 \pm \sqrt{5^{2} - 4 \cdot 3 \cdot - 23}}{2 \cdot 3}$ $x=(-5+-sqrt (5^2 -4*3*-23))/(2*3)$
$x = \frac{- 5 \pm \sqrt{301}}{6}$ $x= (-5+-sqrt301)/6$

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How do you find the zeros of $y = - 3 x^{2} - 5 x + 23$ $y = -3x^2 - 5x + 23$ using the quadratic formula?

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Science

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Humanities

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How do you find the zeros of y = -3x^2 - 5x + 23 y=−3x2−5x+23 y = -3x^2 - 5x + 23 using the quadratic formula?

1 Answer

Explanation:

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How do you find the zeros of $y = - 3 x^{2} - 5 x + 23$ $y = -3x^2 - 5x + 23$ using the quadratic formula?