How do you find the zeros, if any, of $y= -x^2 -5x+2$ using the quadratic formula?

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Answer 1 · 2017-04-07T11:33:08

Zeros are $x ~~ -5.37 , x~~ 0.37$

Quadratic equation is $y=ax^2 +bx+c$

$y= -x^2 -5x +2 ; a = -1 , b= -5 , c=2 ; D= b^2-4*a*c = 25 +8 =33 (+)$
Since D is positve, roots are real.

Roots are $x= -b/(2a)+- sqrt(b^2-4ac)/(2a) or x = 5/-2 +- sqrt 33/-2 or x= -2.5 +- (-2.87) :. x= -2.5 -2.87 ~~ -5.37 or x~~ 0.37$ [Ans]

How do you find the zeros, if any, of y= -x^2 -5x+2y= -x^2 -5x+2using the quadratic formula?