How do you find the zeros, if any, of $y= 3x^2 -2x+ 8$ using the quadratic formula?

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Answer 1 · 2017-02-12T23:44:58

There are only complex zeros: $x = 1/3 +- sqrt(23)/3 i$

Use the quadratic formula where $A = 3, B = -2, C = 8$

$x =( -(-2)+- sqrt((-2)^2-4(3)(8))/(2(3))) = ((2+-sqrt(-92))/6)$

$sqrt(-92) = sqrt(4)sqrt(-23) = 2sqrt(23)i$

Therefore $x = 1/3 +- sqrt(23)/3 i$

If you graph the function it does not cross the x-axis: graph{3x^2-2x+8 [-32.23, 31.8, -5.5, 26.55]}

How do you find the zeros, if any, of y= 3x^2 -2x+ 8 y= 3x^2 -2x+ 8 using the quadratic formula?