How do you find the zeros, if any, of $y= 2x^2 +x- 2$ using the quadratic formula?

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Answer 1 · 2015-12-24T06:17:49

$x=(-1+-sqrt17)/4$

$x=(-b+-sqrt(b^2-4ac))/(2a$

for the quadratic equation

$y=ax^2+bx+c$

Since your equation is

$y=2x^2+x-2$ ,

$a=2$
$b=1$
$c=-2$

Plug these into the quadratic formula:

$x=(-(1)+-sqrt(1^2-(4xx2xx-2)))/(2xx2)$

$x=(-1+-sqrt(1-(-16)))/4$

$x=(-1+-sqrt17)/4$

These are the two times when the function is equal to $0$ (the roots of the function).

How do you find the zeros, if any, of y= 2x^2 +x- 2y= 2x^2 +x- 2using the quadratic formula?