How do you find the y intercept for #y = 12x^2 - 35x + 8#?

1 Answer
Shantelle
Apr 6, 2018

The #y#-intercept is #(0, 8)#.

Explanation:

#y#-intercept is the value at which #x# is zero , or the value of #y# which the point on the line of the graph crosses the #y# axis .

Since #x# has to be #0#, let's substitute #0# for #x# in the equation:
#y = 12x^2 - 35x + 8#
#y = 12(0)^2 - 35(0) + 8#
#y = 0 - 0 + 8#
#y = 8#

Finally, since a #y#-intercept is a point, we must write it as one. So the point is #(0, 8)#.

If we are to graph this, we can see that the graph does indeed have a #y#-intercept of #(0, 8)#:
enter image source here

Hope this helps!

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