How do you find the x intercept of $f (x) = \sqrt{x + 3}$ $f(x)=sqrt(x+3)$ ?

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Answer 1 · 2015-06-01T18:28:43

When $x = - 3$ $x=-3$ then $y = f (- 3) = \sqrt{- 3 + 3} = 0$ $y=f(-3)=sqrt(-3+3)=0$
So the x intercept is at $x = - 3$ $x=-3$ .

How do you find the x intercept of f(x)=√x+3f(x)=sqrt(x+3)?