How do you find the x and y intercepts of #5x-y=3#?

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Answer 1 · 2017-02-27T00:40:16

See the entire solution process below:

To find the x-intercept set #y# equal to #0# and solve for #x#:

#5x - y = 3# becomes:

#5x - 0 = 3#

#5x = 3#

#(5x)/color(red)(5) = 3/color(red)(5)#

#(color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5)) = 3/5#

#x = 3/5# therefore the #x# intercept is #3/5# or #(3/5, 0)#

To find the y-intercept set #x# equal to #0# and solve for #y#:

#5x - y = 3# becomes:

#(5 xx 0) - y = 3#

#0 - y = 3#

#-y = 3#

#color(red)(-1) xx -y = color(red)(-1) xx 3#

#y = -3# therefore the #y# intercept is #-3# or #(0, -3)#