How do you find the x and y intercepts for #y = (x+1)^2#?

1 Answer
Somebody N.
May 8, 2018

y intercept at: #(0,1)#

#x# intercept at: #(-1,0)#

Explanation:

Looking at the graph, we can see that the curve intersects the #bby# axis where #bb(x=0)#, and the curve intersects the #bbx# axis where #bb(y=0)# Using this:

#y# intercept:

#y=(0+1)^2=1#

y intercept at: #(0,1)#

#x# intecept:

#(x+1)^2=0#

Taking roots of both sides:

#x+1=0#

#x=-1#

#x# intercept at #(-1,0)#

graph{y=(x+1)^2 [-5, 5, -1, 6.33]}

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