How do you find the x and y intercepts for #y = -2x + 3#?

2 Answers
Jumbotron
Mar 29, 2018

see a step solution process below;

Explanation:

#y = - 2x + 3#

Since the origin point of intersection is always zero, hence we would use its origin point to locate their intercepts.

To find the intercept of #x#, let #y = 0#

#y = -2x + 3#, where #y = 0#

#0 = -2x + 3#

#2x = 3#

#x = 3/2 = 1.5#

Similarly, to find the intercept of #y#, let #x = 0#

#y = -2x + 3#, where #x = 0#

#y = -2(0) + 3#

#y = 0 + 3#

#y = 3#

Hence the #x and y# intercepts of the equation are #1.5 and 3# respectively..

Jim G.
Mar 29, 2018

#"x-intercept "=3/2," y-intercept "=3#

Explanation:

#"to find the intercepts"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry=0+3=3larrcolor(red)"y-intercept"#

#y=0rArr-2x+3=0rArrx=3/2larrcolor(red)"x-intercept"#
graph{-2x+3 [-10, 10, -5, 5]}

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