How do you find the x and y intercepts for #y=2/3x-8#?
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"Suppose that I don't have a formula for #g(x)# but I know that #g(1)
= 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Apr 29, 2018
Explanation:
#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArry=0-8=-8larrcolor(red)"y-intercept"#
#y=0rArr2/3x-8=0#
#rArr2/3x=8rArrx=(8xx3)/2=12larrcolor(red)"x-intercept"#
graph{(y-2/3x+8)((x-0)^2+(y+8)^2-0.04)((x-12)^2+(y-0)^2-0.04)=0 [-20, 20, -10, 10]}