How do you find the x and y intercepts for #2x - 5y = 10#?

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Answer 1 · 2015-11-17T20:34:47

Rearrange and substitute in y=0 and x=0 to find x and y intercepts respectively.

Rearrange to #y=mx+c#

#5y=2x-10#

#y=2/5x-2#

y intercept is when #x=0#

So #y=-2#

X intercept is when #y=0#

#2/5x-2=0#

#2/5x=2# divide both sides by #2/5#

#x=5#