How do you find the x and y intercept of #3x+0.5y=6#?

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Answer 1 · 2016-11-07T00:42:08

The #y# intercept is 12 and the #x# intercept is 2.

To find the #y# intercept solve for #x = 0#:
#3*0 + 0.5y = 6#

#0.5y = 6#

#(0.5y)/0.5 = 6/0.5#

#y = 12#

To find the #x# intercept solve for #y = 0#:

#3x + 0.5*0 = 6#

#3x = 6#

#(3x)/3 = 6/3#

#x = 2#