How do you find the vertex of #y = 5(x+2)^2 + 7#?

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Answer 1 · 2017-05-01T16:49:54

The vertex form of a parabola of this type is:

#y = a(x-h)^2 + k" [1]"#

where #(h,k)# is the vertex.

Given:

#y = 5(x+2)^2 + 7" [2]"#

We can convert equation [2] into the same form as equation [1] by writing #+2" as" --2#:

#y = 5(x--2)^2 + 7" [3]"#

We observe that the vertex is #(-2,7)#