How do you find the vertex of #f(x)=3(x+1)^2-2#?
1 Answer
Feb 15, 2017
Explanation:
The equation of a parabola in
#color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
where (h ,k) is the vertex and a is a constant.
#f(x)=3(x+1)^2-2" is in this form"#
#"with "h=-1" and "k=-2#
#rArr"vertex "=(-1,-2)#
graph{3(x+1)^2-2 [-10, 10, -5, 5]}
