How do you find the vertex for #y=x^2-4#?

1 Answer
Shantelle
Jun 27, 2018

#(0, -4)#

Explanation:

To find the vertex of a standard quadratic equation #y = ax^2 + bx + c#, first use the formula #(-b)/(2a)# to find the #x#-coordinate of the vertex:
#x = (-b)/(2a) = (-0)/(2(1)) = 0#

Now plug the #x# value of the vertex back into the equation to find the #y# value:
#y = (0)^2 - 4 = -4#

Therefore, the vertex is at #(0, -4)#.

Hope this helps!

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