How do you find the vertex for #y = 2x^2 + 8x -3#?

Question

How do you find the vertex for #y = 2x^2 + 8x -3#?

1 Answer

Impact of this question

1671 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-15T17:40:03

Your quadratic is in the form #y=ax^2+bx+c# where:
#a=2#
#b=8#
#c=-3#
The coordinates of the vertex are:
#x_v=-b/(2a)#
#y_v=-Delta/(4a)#
Where #Delta=b^2-4ac#

Science

Math

Humanities

... and beyond

How do you find the vertex for #y = 2x^2 + 8x -3#?

1 Answer

Related questions

Impact of this question