How do you find the vertex and intercepts for #y=-x^2+2x+3#?
1 Answer
Mar 18, 2016
vertex (1, 4)
Explanation:
x-coordinate of vertex:
y-coordinate of vertex:
y(1) = -1 + 2 + 3 = 4
Vertex (1, 4)
To find y-intercept, make x = 0 --> y = 3
To find x-intercepts, make y = 0, and solve the quadratic equation
Since (a - b + c = 0), use shortcut. The 2 real roots (x -intercepts) are:
- 1 and
