How do you find the values of the other five trigonometric functions of the acute angle A with $tan A = \frac{5}{9}$ $tanA=5/9$ ?

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Answer 1 · 2017-10-23T17:28:44

$tan A = \frac{5}{9}$ $tanA=5/9$

This corresponds to the following triangle

enter image source here

So,

$sin A = \frac{5}{\sqrt{106}}$ $sinA=5/sqrt106$

$cos A = \frac{9}{\sqrt{106}}$ $cosA=9/sqrt106$

$csc A = \frac{\sqrt{106}}{5}$ $cscA=sqrt106/5$

$sec A = \frac{\sqrt{106}}{9}$ $secA=sqrt106/9$

$cot A = \frac{9}{5}$ $cotA=9/5$

How do you find the values of the other five trigonometric functions of the acute angle A with tanA=5/9tanA=59tanA=5/9?