How do you find the value of the six trigonometric functions #t = (7pi)/4#?

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Answer 1 · 2015-05-15T12:46:42

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From basic definitions of the six trigonometric functions

#sin((7pi)/4) = -1/sqrt(2)#

#cos((7pi)/4) = 1/sqrt(2)#

#tan((7pi)/4) = -1#

#csc((7pi)/4) = -sqrt(2)#

#sec((7pi)/4) = sqrt(2)#

#cot((7pi)/4) = -1#