How do you find the value of the discriminant and state the type of solutions given 4a^2=8a-44a2=8a−4?
1 Answer
Sep 15, 2017
Explanation:
"rearrange the quadratic equating to zero"rearrange the quadratic equating to zero
rArr4a^2-8a+4=0larrcolor(blue)" in standard form"⇒4a2−8a+4=0← in standard form
"with "a=4,b=-8,c=4with a=4,b=−8,c=4
Delta=b^2-4ac=(-8)^2-(4xx4xx4)
color(white)(xxxxxxxxx)=64-64=0
color(blue)"Types of solutions"
• " if "Delta>0" roots are real and different"
• " if "Delta=0" roots are real and equal"
• " if "Delta<0" roots are not real"
"here "Delta=0rArr" roots are real and equal"
color(blue)"As a check"
"solving "4a^2-8a+4=0
rArr4(a^2-2a+1)=0
rArr4(a-1)(a-1)=0
rArra=1" or "a=1larrcolor(red)" real and equal"
