How do you find the value of the discriminant and state the type of solutions given $-2x^2-8x-14=-6$ ?

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Answer 1 · 2018-07-26T21:48:08

Determinant $=0$ & the roots are real & equal

The given quadratic equation:

$-2x^2-8x-14=-6$

$x^2+4x+4=0$

Comparing the above equation with the standard form of quadratic equation: $ax^2+bx+c=0$ , we get

$a=1, b=4, c=4$

hence the determinant is given as

$b^2-4ac=4^2-4(1)(4)=0$

Since $b^2-4ac=0$ the roots are real & equal.

How do you find the value of the discriminant and state the type of solutions given -2x^2-8x-14=-6-2x^2-8x-14=-6?