How do you find the value of the discriminant and state the type of solutions given $-6x^2-6=-7x-9$ ?

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Answer 1 · 2017-04-29T04:53:58

Solutions are two rational numbers.

$-6x^2-6=-7x-9$

$hArr6x^2+6-7x-9=0$

or $6x^2-7x-3=0$

Discriminant of quadratic equation $ax^2+bx+c=0$ is $Delta=b^2-4ac$

Here $Delta=(-7)^2-4xx6xx(-3)=49+72=121$ i.e. $Delta > 0$ and is square of $11$

Hence, solutions are two rational numbers.

These are given by $(-b+-sqrtDelta)/(2a)$ and here these are

$7/12+-11/12$ i.e. $3/2$ and $-1/3$

For detail see here.

How do you find the value of the discriminant and state the type of solutions given -6x^2-6=-7x-9-6x^2-6=-7x-9?