How do you find the value of the discriminant and determine the nature of the roots $9m^2+6m+6=5$ ?

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Answer 1 · 2018-04-16T02:07:18

$color(indigo)(D = 0, " and has ONE REAL ROOT, " m = -1/3$

![https://newcollegeswindonmaths.wordpress.com/2016/04/10/core-1-discriminant/]( useruploads.socratic.org )

From the above $"Discriminant " D = b^2 - 4ac$

$9m^2 + 6m + 6 = 5$

$9m^2 + 6m + 6 - 5 = 0$

$9m^2 + 6m _+ 1 = 0$

$"here " a = 9, b = 6, c = 1$

$:. D = b^2 - 4ac = 6^2 - (4 * 9 * 1 ) = 36 - 36 = 0$

$"Hence " color(indigo)(D = 0, " and has ONE REAL ROOT, " m = -1/3$

How do you find the value of the discriminant and determine the nature of the roots 9m^2+6m+6=59m^2+6m+6=5?