How do you find the value of the discriminant and determine the nature of the roots $-2x^2-8x-14=-6$ ?

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How do you find the value of the discriminant and determine the nature of the roots $-2x^2-8x-14=-6$ ?

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Answer 1 · 2016-08-05T16:13:10

Double -root at x = - 2

Explanation:

Bring the quadratic equation to standard form:
$y = -2x^2 - 8x - 8 = 0$
Use the nee Quadratic formula in graphic fomm (Socratic Search)
$D = b^2 - 4ac = 64 - 64 = 0$
Since D = 0, there is a double-root at $x = - b/(2a) = 8/-4 = - 2$
graph{-2x^2 - 8x - 8 [-10, 10, -5, 5]}

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How do you find the value of the discriminant and determine the nature of the roots $-2x^2-8x-14=-6$ ?

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How do you find the value of the discriminant and determine the nature of the roots -2x^2-8x-14=-6-2x^2-8x-14=-6?

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How do you find the value of the discriminant and determine the nature of the roots $-2x^2-8x-14=-6$ ?