How do you find the value of the discriminant and determine the nature of the roots $9n^2-3n-8=-10$ ?

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How do you find the value of the discriminant and determine the nature of the roots $9n^2-3n-8=-10$ ?

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Answer 1 · 2017-05-12T15:43:54

No real roots.

Explanation:

Solve the quadratic equation:
$f(n) = 9n^2 - 3n - 8 + 10 = 9n^2 - 3n + 2 = 0$
Use the improved quadratic formula (Socratic Search).
$D = d^2 = b^2 - 4ac = 9 - 72 = - 63 < 0$
Since D < 0, there are no real roots. There are 2 imaginary roots.

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How do you find the value of the discriminant and determine the nature of the roots $9n^2-3n-8=-10$ ?

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Explanation:

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How do you find the value of the discriminant and determine the nature of the roots 9n^2-3n-8=-109n^2-3n-8=-10?

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How do you find the value of the discriminant and determine the nature of the roots $9n^2-3n-8=-10$ ?