How do you find the value of the discriminant and determine the nature of the roots $2 x^2 - 3x +1=0$ ?

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Answer 1 · 2018-03-13T11:30:49

Solution: $x=1 and x= 1/2$

$2x^2-3x+1=0$

Comparing with standard quadratic equation $ax^2+bx+c=0$

$a=2 ,b=-3 ,c=1$ Discriminant, $D= b^2-4ac$ or

$D=9 - 8 =1$ . If discriminant positive, we get two real solutions,

if it is zero we get just one solution, and if it is negative we get

complex roots. Discriminant is positive here , so it has two

distinct root . Quadratic formula: $x= (-b+-sqrtD)/(2a)$ or

$x= (3+-sqrt1)/4 :. x= (3+-1)/4 :. x=1 and x= 1/2$

Solution: $x=1 and x= 1/2$ [Ans]

How do you find the value of the discriminant and determine the nature of the roots 2 x^2 - 3x +1=02 x^2 - 3x +1=0?