How do you find the value of the discriminant and determine the nature of the roots $x^2 – 64 = 0$ ?

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Answer 1 · 2018-04-16T01:57:09

$color(brown)( D > 0) color(green)(" (+VE), given equation has " color(blue)("TWO REAL ROOTS " (+-8)$

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$x^2 - 64 = 0$

It is in the form $ax^2 + bx + c = 0, " with "a = 1, b = 0, c = -64$

$"Discriminant " D = b^2 - 4 a c = 0 - (4 * 1 * -64) = 256$

Since $color(brown)( D > 0) color(green)(" (+VE), given equation has " color(blue)("TWO REAL ROOTS " (+-8)$

How do you find the value of the discriminant and determine the nature of the roots x^2 – 64 = 0 x^2 – 64 = 0 ?