How do you find the value of the discriminant and determine the nature of the roots $-x^2-9=6x$ ?

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How do you find the value of the discriminant and determine the nature of the roots $-x^2-9=6x$ ?

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Answer 1 · 2018-04-17T19:23:48

$D$ =0 and the roots are real and equal.

Explanation:

We have, $x^2+6x+9$ =0 [On arrangement]
Thus, $a$ =1, $b$ =6 and $c$ =9
Thus, $D=b^2-4ac$
= $(6)^2-4xx1xx9$
= $36-36$ =0
Thus,the roots are real and equal to $x=-3,-3$

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How do you find the value of the discriminant and determine the nature of the roots $-x^2-9=6x$ ?

1 Answer

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Science

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Humanities

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How do you find the value of the discriminant and determine the nature of the roots -x^2-9=6x-x^2-9=6x?

1 Answer

Explanation:

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How do you find the value of the discriminant and determine the nature of the roots $-x^2-9=6x$ ?