How do you find the sum of the infinite series #Sigma6(1/10)^i# from i=1 to #oo#? Calculus Introduction to Integration Sigma Notation 1 Answer t0hierry Jul 5, 2017 #1 /( 1/10-1)6# Explanation: It is #sum (a^n)= 1/((1-1/a)) = 10/9*6# Answer link Related questions How does sigma notation work? How do you use sigma notation to represent the series #1/2+1/4+1/8+…#? Use summation notation to express the sum? What is sigma notation for an arithmetic series with first term #a# and common difference #d# ? How do you evaluate the sum represented by #sum_(n=1)^5n/(2n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(8)1/(n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(10)n^2# ? What is sigma notation for a geometric series with first term #a# and common ratio #r# ? What is the value of #1/n sum_{k=1}^n e^{k/n}# ? Question #07873 See all questions in Sigma Notation Impact of this question 2223 views around the world You can reuse this answer Creative Commons License