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How do you find the sum of #Sigma [(i-1)^2+(i+1)^3]# where i is [1,4]?

1 Answer

Nov 13, 2017

#238#

Explanation:

#sum_(i=1)^4 [(i-1)^2+(i+1)^3]#

#=sum_(i=1)^4 (i^2-2i+1+i^3+3i^2+3i+1)#

#=sum_(i=1)^4 (i^3+4i^2+i+2)#

#=((4*5)/2)^2+4*(4*5*9)/6+(4*5)/2+2*4#

#=238#

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