How do you find the sum given #Sigma k(k-2)# from k=3 to 6?

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How do you find the sum given #Sigma k(k-2)# from k=3 to 6?

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Answer 1 · 2016-10-31T13:23:43

# sum_(k=3)^(k=6) k(k-2) = 50 #

Explanation:

# sum_(k=3)^(k=6) k(k-2) = 3(3-2) + 4(4-2) + 5(5-2) + 6(6-2) #
# :. sum_(k=3)^(k=6) k(k-2) = 3(1) + 4(2) + 5(3) + 6(4) #
# :. sum_(k=3)^(k=6) k(k-2) = 3 + 8 + 15 + 24 #
# :. sum_(k=3)^(k=6) k(k-2) = 50 #

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How do you find the sum given #Sigma k(k-2)# from k=3 to 6?

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