How do you find the sum given #Sigma(2i+1)# from i=1 to 5?

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How do you find the sum given #Sigma(2i+1)# from i=1 to 5?

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Answer 1 · 2016-10-31T13:57:29

# sum_(i=1)^(i=5)(2i+1) = 35 #

Explanation:

# sum_(i=1)^(i=5)(2i+1) = (2(1)+1) + (2(2)+1) + (2(3)+1) + (2(4)+1) + (2(5)+1) #
# :. sum_(i=1)^(i=5)(2i+1) = (2+1) + (4+1) + (6+1) + (8+1) + (10+1) #
# :. sum_(i=1)^(i=5)(2i+1) = 3 + 5 + 7 + 9 + 11 #
# :. sum_(i=1)^(i=5)(2i+1) = 35 #

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How do you find the sum given #Sigma(2i+1)# from i=1 to 5?

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