How do you find the square root of 16/121?

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How do you find the square root of 16/121?

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Answer 1 · 2018-03-31T11:04:35

$+-4/11$

Explanation:

$16" and " 121" are both " color(blue)"perfect squares"$

$"that is "16=4^2" and "121=11^2$

$"also "16=(-4)^2" and "121=(-11)^2$

$rArrsqrt(16/121)=+-4/11$

Answer 2 · 2018-04-01T19:23:18

$+-4/11$

Explanation:

We have the following

$sqrt(16/121)$ which is equivalent to:

$=+-sqrt16/sqrt121$

Notice, the numerator and denominator are both perfect squares, that is, we get a integer as an answer. This evaluates to:

$+-4/11$

NOTE: The $+-$ sign comes from the fact that when we take the square root of a number, we get a positive and a negative number.

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How do you find the square root of 16/121?

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