How do you find the solution to $4(sintheta+1)=6-sintheta$ if $0<=theta<2pi$ ?

Question

1581 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-20T16:46:31

$theta= arc sin (2/5), pi- arc sin (2/5)$

Simplify the expression first by solving it for $sintheta$ ,

$4sin theta +4= 6-sin theta$

$5sin theta=2$

$sin theta = 2/5$

This gives the solution, $theta= arc sin (2/5)$ . The other solution in the given interval would be $pi- arc sin(2/5)$

How do you find the solution to 4(sintheta+1)=6-sintheta4(sintheta+1)=6-sintheta if 0<=theta<2pi0<=theta<2pi?