How do you find the solution to 3tantheta+sqrt3=03tanθ+√3=0 if 0<=theta<3600≤θ<360?

1 Answer
Binayaka C.
Nov 23, 2016

Solution: in interval 0<= theta <360 , theta=150^0, theta=330^00≤θ<360,θ=1500,θ=3300

Explanation:

3 tan theta +sqrt3 =0 or 3 tan theta = -sqrt3 or tan theta = -sqrt3/33tanθ+√3=0or3tanθ=−√3ortanθ=−√33; We know, tan(pi-pi/6)=-sqrt3/3 and tan(2pi-pi/6)=-sqrt3/3 :. theta=(pi-pi/6)=150^0 and theta=(2pi-pi/6)=330^0

Solution: in interval 0<= theta <360 , theta=150^0,330^0[Ans]

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