3(tan theta - 2) = 2 tan theta - 7color(white)(aaa) 3(tanθ−2)=2tanθ−7aaabringing variables to L H S and constants to R H S,
3 tan theta - 2 tan theta = -7 + 63tanθ−2tanθ=−7+6
tan theta = -1tanθ=−1
theta = (3pi)/4, (7pi) / 4 for 0 <= theta < 360 color (white)(aaa)θ=3π4,7π4for0≤θ<360aaa tan is negative in 2^(nd), 4^(th)2nd,4th quadrants.