How do you find the solution to $10sintheta+1=3-2sintheta$ if $0<=theta<2pi$ ?

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How do you find the solution to $10sintheta+1=3-2sintheta$ if $0<=theta<2pi$ ?

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Answer 1 · 2017-02-16T01:42:36

$9^@59, 179^@41$

Explanation:

10sin t + 1 = 3 - 2sin t
12sin t = 2
$sin t = 2/12 = 1/6$
Calculator -->
$sin t = 1/6$ --> $t = 9^@59$
Unit circle gives another t that has the same sin value:
$t = 180 - 9.59 = 179^@41$

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How do you find the solution to $10sintheta+1=3-2sintheta$ if $0<=theta<2pi$ ?

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How do you find the solution to 10sintheta+1=3-2sintheta10sintheta+1=3-2sintheta if 0<=theta<2pi0<=theta<2pi?

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How do you find the solution to $10sintheta+1=3-2sintheta$ if $0<=theta<2pi$ ?