How do you find the slope of a line that is perpendicular to $2 x + y = 4$ $2x+y=4$ ?

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Answer 1 · 2016-11-30T11:32:09

The slope of the line is $\frac{1}{2}$ $1/2$

The product of the slopes of two perpendicular lines is $- 1$ $-1$ .

The slope of the line $2 x + y = 4 or y = - 2 x + 4$ $2x+y=4 or y=-2x+4$ is $- 2$ $-2$ (Compare with $y = m x + c)$ $y=mx+c)$

Let $m_{2}$ $m_2$ is the slope of the perpendicular line.
$m_2*(-2)=-1 :. m_2=1/2$

So the slope of the line is $1/2$ [Ans]

Answer 2 · 2016-11-30T11:48:54

Slope of lines perpendicular to $y$ is $1/2$

$2x+y=4$

$y =-2x+4$

A straight iine in slope $(m)$ and intercept $(c)$ form has the equation:
$y=mx+c$

Hence this example $m=-2$

Lines perpendicular to $y$ will have a slope $(m_1)$ that satisfies $m*m_1=-1$

$:. m_1 = -1/-2 = 1/2$

How do you find the slope of a line that is perpendicular to 2x+y=42x+y=42x+y=4?