How do you find the slope-intercept form of the equation of the line passing through the points #(3/4, 3/2) and (-4/3, 7/4)#?

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Answer 1 · 2017-02-16T14:48:09

#y = -3/25x +1 59/100#

#m = -3/25 and c = 1.59#

Lets find the slope first: #m = (y_2-y_1)/(x_2-x_1)#

# rarr" " m = (7/4-3/2)/(-4/3-3/4)#

#m= ((7-6)/4)/((-16-9)/12) = (1/4)/((-25)/12)#

#m = (1xxcancel12^3)/(cancel4xx-25) = -3/25#

Substitute #m and #one point into #y-y_1 =m(x-x_1)#

#m = -3/25 " and the point, " (3/4, 3/2)#

#y-3/2 = -3/25(x-3/4)#

#y = -3/25x+9/100+3/2#

#y = -3/25x +1 59/100#