How do you find the slope intercept form of the equation of the line that passes through (-1, 5) and is parallel to #4x+2y=8#?

1 Answer
Nov 4, 2016

The equation of the line in slope intercept form is #y=-2x+3#.

Explanation:

The slope of the line #4x+2y=8 or 2y= -4x+8 or y= -2x+4# is #-2#(obtained by comparing with the standard form of equation #y=mx+c#)

Parallel lines have same slope .

Thus line passing through #(-1,5)# , parallal to the line #y= -2x+4# has slope #m=-2#

So the equation of the line in slope intercept form is #y=-2x+c#

The point #(-1,5)# is on the line , so it satisfies the equation #y=-2x+c :. 5 = -2* -1 + c or c=5-2=3#.
Hence the equation of the line is #y=-2x+3#. [Ans]