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How do you find the slope-intercept form for the equation of the line which passes through the point (–3, 2) and the origin?

1 Answer

Jun 5, 2016

$y = - \frac{2}{3} x + 0 or just y = - \frac{2}{3} x$ $y = -2/3x + 0 " or just " y = -2/3x$

Explanation:

Slope intercept form or standard from is $y = m x + c$ $y = mx + c$

The slope is found from $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1)/(x_2 - x_1)$

$m = \frac{2 - 0}{- 3 - 0} = - \frac{2}{3}$ $m = (2 - 0)/(-3 -0) = -2/3$

The y intercept is obviously 0 (origin)
Equation is therefore $y = - \frac{2}{3} x + 0$ $y = -2/3x + 0$

The 0 dos not need to be written.

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