How do you find the slope and y-intercept for the line #5x-y+2=0#?

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Answer 1 · 2018-03-05T14:41:59

Just arrange the equation in #y=mx+c# form,where #m# is the slope and #c# is the #Y# intercept.

So,given equation in #5x-y+2=0#

or, #y=5x+2#

so,comparing with #y=mx+c# we get, #m=5# and #c=2#

Now,see the graph below to match the result obtained. graph{5x-y+2=0 [-10, 10, -5, 5]}

Answer 2 · 2018-03-05T14:43:41

See a solution process below:

We can put the equation for the line in slope-intercept form. The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

#5x - y + 2 = 0#

#5x - y + color(red)(y) + 2 = 0 + color(red)(y)#

#5x - 0 + 2 = y#

#5x + 2 = y#

#y = color(red)(5)x + color(blue)(2)#

Therefore: