How do you find the slope and intercepts of x-2y=8?

1 Answer
Dec 8, 2016

"slope " =1/2," intercepts are " -4 , 8

Explanation:

The equation of a line in color(blue)"slope-intercept form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))
where m represents the slope and b, the y-intercept.

"Rearrange " x-2y=8" into this form"

Leave - 2y on the left side and subtract x from both sides.

cancel(x)cancel(-x)-2y=-x+8

rArr-2y=-x+8

divide ALL terms on both sides by - 2

(cancel(-2) y)/cancel(-2)=(-1)/(-2)x+8/(-2)

rArry=1/2x-4larr" now in above form"

rArr"slope " =1/2" and y-intercept " =-4

To find the x-intercept, substitute y = 0 into the equation and solve for x.

rArrx-(2xx0)=8rArrx=8" is the x-intercept"