How do you find the slope and intercepts of #x-2y=8#?

1 Answer
Jim G.
Dec 8, 2016

#"slope " =1/2," intercepts are " -4 , 8#

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

#"Rearrange " x-2y=8" into this form"#

Leave - 2y on the left side and subtract x from both sides.

#cancel(x)cancel(-x)-2y=-x+8#

#rArr-2y=-x+8#

divide ALL terms on both sides by - 2

#(cancel(-2) y)/cancel(-2)=(-1)/(-2)x+8/(-2)#

#rArry=1/2x-4larr" now in above form"#

#rArr"slope " =1/2" and y-intercept " =-4#

To find the x-intercept, substitute y = 0 into the equation and solve for x.

#rArrx-(2xx0)=8rArrx=8" is the x-intercept"#

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