How do you find the slope and intercepts of x-2y=8?
1 Answer
Dec 8, 2016
Explanation:
The equation of a line in
color(blue)"slope-intercept form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))
where m represents the slope and b, the y-intercept.
"Rearrange " x-2y=8" into this form" Leave - 2y on the left side and subtract x from both sides.
cancel(x)cancel(-x)-2y=-x+8
rArr-2y=-x+8 divide ALL terms on both sides by - 2
(cancel(-2) y)/cancel(-2)=(-1)/(-2)x+8/(-2)
rArry=1/2x-4larr" now in above form"
rArr"slope " =1/2" and y-intercept " =-4 To find the x-intercept, substitute y = 0 into the equation and solve for x.
rArrx-(2xx0)=8rArrx=8" is the x-intercept"