How do you find the slope and intercept of #–x – 8y = –32#?

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How do you find the slope and intercept of #–x – 8y = –32#?

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Answer 1 · 2016-03-19T10:36:28

Slope #= -1/8# x-intercept #= 32# y-intercept #=4#

Explanation:

# -x-8y = -32 or 8y = -x +32 or y = -1/8*x +4# So slope# = -1/8# and y-intercept # =4# x-intercept can be obtained by puuting y=0 in the equation. # -x + 32 =0 or x=32# so x-intercept #=32# graph{-1/8*x+4 [-80, 80, -40, 40]}[Ans]

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How do you find the slope and intercept of #–x – 8y = –32#?

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