How do you find the slope and intercept of #7x + 3y=4#?

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Answer 1 · 2018-07-06T00:17:20

#-7/3# & #4/3#

Given that

#7x+3y=4#

#3y=-7x+4#

#y=-7/3x+4/3#

Comparing above equation with the slope-intercept form of straight line: #y=mx+c# we get

Slope: #m=-7/3#

y-Intercept: #c=4/3#

Answer 2 · 2018-07-06T00:26:28

Slope= #-7/3#

#y#-intercept= #4/3#

We can find the #y#-intercept by setting #x# to zero, because that is exactly what the #y#-intercept means...when #x=0# we are on the #y# axis.

If we set #x# to zero, that term disappears, and we are left with

#3y=4=>y=4/3#

This is our #y#-intercept.

To go about finding our slope, we can convert this equation into slope-intercept form

#y=mx+b# where #m# is the slope and #b# is the #y#-intercept.

#7x+3y=4#

We want just a #y# on the left, so we can subtract #7x# from both sides to get

#3y=-7x+4#

Dividing all terms by #3#, we get

#y=-7/3x+4/3#

Our slope is the coefficient on #x#, which in our case, is #-7/3#.

The #y#-intercept is the constant and we see that this is #4/3#.

Hope this helps!