How do you find the slope and intercept of #5(x-3y)=2(x+3)#?

1 Answer
Shwetank Mauria
Aug 29, 2016

Slope of the line is #1/5# and intercept on #y#-axis is #-2/5#

Explanation:

The equation of a line in slope intercept form is #y=mx+c#, where #y# is expressed in terms of #x# and then #m#, the coefficient of #x#, is slope and #c# the constant term is the value of intercept made by the line on #y#-axis.

In the equation #5(x-3y)=2(x+3)#, we simplify and write #y# in terms of #x#.

#5(x-3y)=2(x+3)#

#hArr5x-15y=2x+6# or

#-15y=2x-5x+6# or

#-15y=-3x+6# or

#y=(-3)/(-15)x+6/(-15)# or

#y=1/5 x-2/5#

Hence slope of the line is #1/5# and intercept on #y#-axis is #-2/5#.

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