How do you find the slope and intercept of #2x-5y= -10#?

1 Answer
Deepak G.
Jul 25, 2016

#x#-intercept is #x=-5#

#y#-intercept is #y=2#

slope=#2/5#

Explanation:

#2x-5y=-10#
#x#-intercept is when #y=0#
So by putting #y=0# in the above equation we get
#2x-5(0)=-10#
or
#2x-0=-10#
or
#2x=-10#
or
#x=-10/2#
or
#x=-5# --------------Ans #1#

#y#-intercept is when #x=0#
So by putting #x=0# in the equation #2x-5y=-10# we get
#2(0)-5y=-10#
or
#0-5y=-10#
or
#-5y=-10#
or
#5y=10#
or
#y=10/5#
#y=2# --------------Ans #2#

In the equation #y=mx+c; m# is the slope
So we can rewrite equation #2x-5y=-10#
as
#5y=2x+10#
or
#y=(2/5)x+10/5#
or
#y=(2/5)x+2#

Hence slope=#2/5# ----------Ans #3#

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