How do you find the six trigonometric functions of #(-pi)/3#?

1 Answer
Alan P.
Jun 3, 2015

#pi/3# (and by extension #(-pi)/3# is an angle of one of the standard trigonometric triangles:
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From this we can see
#color(white)("XXXX")##sin(-pi/3) = -sqrt(3/2)#
#color(white)("XXXX")##color(white)("XXXX")##csc(-pi/3) = -2/sqrt(3)#

#color(white)("XXXX")##cos(-pi/3) = 1/2#
#color(white)("XXXX")##color(white)("XXXX")##sec(-pi/3) = 2#

#color(white)("XXXX")##tan(-pi/3) = -sqrt(3)#
#color(white)("XXXX")##color(white)("XXXX")##cot(-pi/3) = - 1/sqrt(3)#

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